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what are the solutions to to the equation x^2+4x+4=12

Sagot :

The solutions are (x-2-2sqrt3)(x-2+2sqrt3)
loneguy

Answer:

[tex]x = -2 +2\sqrt 3\\\\x = -2 -2\sqrt 3[/tex]

Step by step explanation:

[tex]~~~~~~x^2 +4x +4 = 12\\\\\implies x^2 +2\cdot 2x + 2^2 = 12\\ \\\implies (x+2)^2 = 12\\\\\implies x +2 = \pm\sqrt{12}\\\\\implies x = -2 \pm\sqrt{12}\\\\\implies x = -2\pm\sqrt{4 \times 3}\\\\\implies x = -2 \pm2\sqrt 3[/tex]

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