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A chemist wishes to perform the following reaction: N2 + 3 H2 → 2 NH3 If only 14.0 g of N2 is available, what is the minimum amount, in grams, of H2 needed to completely react with this quantity of N2?

Sagot :

Answer:

3 grams

Explanation:

14 g of N2   is 1/2 mole

  If you halve the N2   in the balanced equation , you have to halve the H2 down to 1.5 moles of H2    which is 3 grams

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