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How many half-lives of time have passed when only a little more than 3% of a sample
original C-14 remains?


Sagot :

Answer:

5.06 half lives

Explanation:

1/2 ^n  = .03             (.03 is 3% in decimal)

                         log both sides

n log 1/2 = log .03

n = 5.06  half lives