Answered

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There is a rack of 11 billiards balls, numbered from 1 to 11. If one ball is selected at random, determine the odds in favor of it being at an even-number ball.

Sagot :

sarajeffries7

Answer:

5/11 odds  /   45.45% chance of being even-numbered

Step-by-step explanation:

There are 5 even-numbered balls (2, 4, 6, 8, 10) and 6 odd-numbered balls  (1, 3, 5, 7, 9, 11). So, 5 / 11 balls are even-numbered

if a ball is selected, it has a chance of 5/11 for being even-numbered

5/11 also = 45.45 % [rounded] chance of being even-numbered    

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