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Segment GH is shown on the graph.

What are the coordinates of the point that divides the
segment into a 3:2 ratio?
O (-7.5, 0.5)
O (0.5, -7.5)
O (-1.2,-2.2)
O (-2.2,-1.2)

Segment GH Is Shown On The Graph What Are The Coordinates Of The Point That Divides The Segment Into A 32 Ratio O 75 05 O 05 75 O 1222 O 2212 class=

Sagot :

The coordinates of the point that divides the segment into a 3:2 ratio is (-2.2, -1.2)

How to determine the coordinate?

The points are given as:

G = (-4,3)

H = (-1,-4)

Ratio, m : n = 3 : 2

The coordinate of the point is calculated using:

[tex](x,y) = \frac{1}{m + n} * (mx_2 + nx_1, my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{3 + 2} * (3 * -1 + 2 * -4, 3 * -4 + 2 * 3)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (-11, -6)[/tex]

Evaluate the product

(x,y) = (-2.2, -1.2)

Hence, the coordinate of the point is (-2.2, -1.2)

Read more about line segment ratio at:

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