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Find the zeros of the function by rewriting in intercept form.

Y=2X^2-4x

y=2C^2-11X-21

I need the answer and the work please.

Sagot :

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The intercept form is [tex]y=a(x-p)(x-q)[/tex] where p, q - the zeroes of a function.

1.
[tex]y=2x^2-4x \\ y=2x(x-2) \\ y=2(x-0)(x-2) \\ \hbox{the zeroes - }\boxed{x=0 \ and \ x=2}[/tex]

2.
[tex]y=2x^2-11x-21 \\ y=2x^2-14x+3x-21 \\ y=2x(x-7)+3(x-7) \\ y=(2x+3)(x-7) \\ y=2(x+\frac{3}{2})(x-7) \\ y=2(x-(-\frac{3}{2}))(x-7) \\ \hbox{the zeroes - }\boxed{x=-\frac{3}{2} \ and \ x=7}[/tex]
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