Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
[tex]P=(\stackrel{\stackrel{x}{adjacent}}{2\sqrt{2}}~~,~~\stackrel{\stackrel{y}{opposite}}{2\sqrt{2}}) \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{2\sqrt{2}}}{\underset{adjacent}{2\sqrt{2}}}\implies \theta =tan^{-1}\left( \cfrac{2\sqrt{2}}{2\sqrt{2}} \right)\implies \theta =tan^{-1}(1)\implies \theta =45^o[/tex]
Make sure your calculator is in Degree mode.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
