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(A) Find the slope of the line that passes through the given points.
(B) Find the standard form of the equation of the line.
(C) Find the slope-intercept form of the equation of the line.
(-3,4) and (6,4)
(A) Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
OA. The slope is m =
(Type an integer or a simplified fraction.)
B. The slope is not defined.


Sagot :

[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{0}{6 +3}\implies 0[/tex]

hmmm a line with a slope of 0 is a horizontal one, and it has no slope-intercept form.

Check the picture below.

View image jdoe0001