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The Niagara Falls ferris wheel has a diameter of 48 meters, and one revolution takes 2.25 minutes to complete. Riders can see Niagara falls if they are higher than 41 meters above the ground. What are the time intervals when the rider can see Niagara Falls if they complete 3 complete revolutions, if the rider gets on at a height of 0.5 m at t=0 min?

Sagot :

The time intervals when the riders could see Niagara falls are; 0.834 < t < 1.416 and (3.084, 3.666)

How to interpret Cycle Graphs?

From the diagram attached, we can say that;

Period = 2π/k

where;

k = 2π/2.25

k = 8π/9

Thus;

h(t) = -(48/2) cos (8π/9)t + ((48/2) + 0.5)

h(t) = -24cos (8π/9)t + 24.5

Riders can see Niagara falls if they are higher than 41 meters above the ground. Thus;

41 = -24cos (8π/9)t + 24.5

41 - 24.5 = -24cos (8π/9)t

16.5 = -24cos (8π/9)t

-0.6875 = cos (8π/9)t

cos⁻¹0.6875 = (8π/9)t

t = 0.834 min

Thus, time interval is between;

0.834 < t < (2.25 - 0.834)

⇒ 0.834 < t < 1.416 and

(2.25 + 0.834) < t < (2.25 + 1.416)

⇒ (3.084, 3.666)

Read more about Cycle Graphs at; https://brainly.com/question/24461724

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