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determine how many grams of N2 are produced from the reaction of 8.73
g of H2O2 and 5.16
g of N2H4.


Sagot :

Taking into account the reaction stoichiometry, 4.515 grams of N₂ can be produced from 8.73 grams of H₂O₂ and 5.16 grams of N₂H₄.

Reaction stoichiometry

In first place, the balanced reaction is:

N₂H₄ + 2 H₂O₂ → N₂ + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • N₂H₄: 1 mole
  • H₂O₂: 2 moles
  • N₂: 1 mole
  • H₂O: 4 moles

The molar mass of the compounds is:

  • N₂H₄: 32 g/mole
  • H₂O₂: 34 g/mole
  • N₂: 28 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • N₂H₄: 1 mole ×32 g/mole= 32 grams
  • H₂O₂: 2 moles ×34 g/mole= 34 grams
  • N₂: 1 mole ×28 g/mole= 28 grams
  • H₂O: 4 moles ×18 g/mole= 18 grams

Limiting reagent

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

Limiting reagent in this case

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 34 grams of H₂O₂ reacts with 32 grams of N₂H₄, 8.73 grams of H₂O₂ reacts with how much mass of N₂H₄?

[tex]mass of N_{2} H_{4} =\frac{8.73 grams of H_{2} O_{2}x 32 grams of N_{2} H_{4} }{34grams of H_{2} O_{2}}[/tex]

mass of N₂H₄= 8.22 grams

But 8.22 grams of N₂H₄ are not available, 5.16 grams are available. Since you have less mass than you need to react with 8.73 grams of H₂O₂, N₂H₄ will be the limiting reagent.

Mass of N₂ formed

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of N₂H₄ form 28 grams of N₂, 5.16 grams of N₂H₄ form how much mass of N₂?

[tex]mass of N_{2} =\frac{5.16 grams of N_{2} H_{4} x28 grams of N_{2}}{32 grams of N_{2} H_{4} }[/tex]

mass of N₂= 4.515 grams

Then, 4.515 grams of N₂ can be produced from 8.73 grams of H₂O₂ and 5.16 grams of N₂H₄.

Learn more about the reaction stoichiometry:

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