shazilmohamed16
Answered

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. In the counter-current heat exchanger, the liquid food is cooled from 73°C to 38°C at the rate of 2500 kg h', using water at 15°C which leaves the heat exchanger at 40°C. The pipework 2.5cm in diameter is constructed from stainless steel 3mm thick; the surface film heat transfer coefficients are 1200 Wm³K on the liquid food side and 3000Wm³K-¹ on the water side of the pipe. Calculate the Overall heat transfer coefficient and the length of pipe required (Note: specific heat of water and liquid food is 4.18 kj/kg°C and 3.17 kj/kg C respectively) (6marks).

Sagot :

The Overall heat transfer coefficient and the length of pipe required was 9.48x10 J and the length of pipe required is 57m.

What is the supposed via way of means of heat transfer?

Warmness transfer, all or any of numerous forms of phenomena, taken into consideration as mechanisms, that deliver power and entropy from one place to another. The unique mechanisms are commonly known as convection, thermal radiation, and conduction.

  1. 1/U= 1/ha+x/k+1/hk
  2. =1/1200+3/21+1/3000
  3. = 1.31 x 10^-3.
  4. Now U= 763.6 Wm^-2-C-1.
  5. To length of pipe required= Q = UAdelta m.
  6. = A=3.142xDl
  7. = l =4.48/3.142x0.025
  8. =57 m.

Read more about the length :

https://brainly.com/question/2217700

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