Answered

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An athlete is running at a constant velocity with a javelin held in his right hand. The force he is applying on the javelin to carry it is 5.0 newtons. If he covers a distance of 10 meters, what work has he done on the javelin?

Sagot :

ArisingPlayer

Answer:

50J

Explanation:

Work done=Fd

=5×10

=50J
50J
Equation= fd
= 5x10
=50
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