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Josefin is 32 years younger than Annete. How many years ago was Annetes age twice Josefins age if Annete is 74 now.

Sagot :

Annette's age will be twice Josefin's age 10 years ago.

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division

Given that:-

Josefin is 32 years younger than Annette. How many years ago was Annette's age twice Josefins age if Annette is 74 now.

So we can see that their present age Annette is 74 so the present age of Josefin will be 32 years lesser.

J = 74 - 32 = 42 years

The before 10 years ages of both the Josefin and Annettes will be:-

J = 42 - 10 = 32

A = 74 - 10 = 64

The ratio of the ages is:-

A / J = 64 / 32 = 2

A = 2 J

Therefore Annette's age will be twice Josefin's age 10 years ago.

To know more about Expression follow

https://brainly.com/question/723406

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