(a) The acceleration of the two block is determined as 0.93 m/s².
(b) The tension in the string is 5.78 N.
Net force on the aluminum block
The net force on the aluminum block is calculated as follows;
[tex]T - \mu_a m_a g = m_a a \ --- \ (1)[/tex]
Net force on the copper block
The net force on the copper block is calculated as follows;
[tex]m_cg sin(30) - T -\mu _cm_c gcos(30) = m_c a --- (2)[/tex]
where;
- T is tension in the string
- ma is mass of aluminum
- mc is mass of copper
- g is acceleration due to gravity
Solve for T using (1) and (2)
[tex]a = g(\frac{m_c sin30\ - \ \mu _c m_c cos30 \ - \mu_ a m_a}{ma_a + m_c} )\\\\a = 9.8(\frac{6 sin30\ - \ 0.2 (6) cos30 \ - 0.2 (6)}{2 +6} )\\\\a = 0.93 \ m/s^2[/tex]
Tension in the string
From equation (1);
T = μm_ag + m_aa
T = 0.2(2)(9.8) + 2(0.93)
T = 5.78 N
Learn more about tension here: https://brainly.com/question/918617
#SPJ1
