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The cutoff frequency for a certain element is 1.22 x 10^15 Hz. What is its work function in eV?

Sagot :

The work function in eV for the given cutoff frequency is  5.05 eV.

What is cutoff frequency?

The work function is related to the frequency as

Wo = h x fo

where, fo = cutoff frequency and h is the Planck's constant

Given is the cutoff frequency for a certain element is 1.22 x 10¹⁵ Hz

Wo = 6.626 x 10⁻³⁴ x  1.22 x 10¹⁵ Hz / 1.6 x 10⁻¹⁹

Wo = 5.05 eV

Thus, the work function is  5.05 eV

Learn more about cutoff frequency.

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