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sin2pheta/sinpheta + 1+cos2pheta/cospheta =

4sinpheta
4cospheta
2cospheta
2sinpheta​


Sagot :

Answer:

4cos(θ)

{4cospheta}

Answer:

4cos(θ)

{4cospheta}

Step-by-step explanation:

[note, brainly doesn't allow pheta to be entered as a symbol when writing an equation, so I had to write it out, my apologies]

[tex]\frac{\sin \left(2pheta \right)}{\sin \left(pheta\right)}+\frac{1+\cos \left(2pheta\right)}{\cos \left(pheta\right)}\\[/tex]

[tex]\frac{1+\cos \left(2pheta\right)}{\cos \left(pheta\right)}\ = 2\cos \left(pheta\right)[/tex]

[tex]\frac{\sin \left(2pheta \right)}{\sin \left(pheta\right)}=2\cos \left(pheta\right)[/tex]

2cos(θ) + 2cos(θ) = 4cos(θ)

so, 4cos(θ) is your answer

(4cospheta)

hope this helps!! :)