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A sealable bag holds 3.79 L of
gas. How many moles of H₂
gas are needed to fill the bag
at 1.0 atm and 293 K?

A Sealable Bag Holds 379 L Of Gas How Many Moles Of H Gas Are Needed To Fill The Bag At 10 Atm And 293 K class=

Sagot :

The H₂ gas are needed 0.157moles to fill the bag .

For solving this problem  we use the ideal gas equation. It is also called the general gas equation . This equation use for a hypothetical ideal gas. . It has several limitations. It was first stated by Benoit Paul Emile Clapeyron in 1834 . The ideal gas law is  written by an empirical form:

                                  PV = n R T

where-

            P = Pressure

            V = volume

            T = Temperature

            n =  The amount of substance

            R =  Ideal gas constant

Now we have the values of these terms as-

             P = 1 atm , V = 3.79L ,  T = 293K

 and     R = 0.0826 L/atm

For getting moles of hydrogen we can use the values of variables in ideal gas equation as -

                     P V = n R T

Now              (1 atm) × ( 3.79L ) = n ×  ( 0.0826 L/atm)  × ( 293K)

                                            n = (1 × 3.79) ÷ (0.0826 x 293)

                                              =  0.157 moles

So that the 0.157moles of H₂ gas are needed for fill the bag .

Learn more about the ideal gas here:

https://brainly.in/question/11882

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