Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The probability that one will win back at least the cost of three tickets is approximately 0.31744. This is solved using Binomial Distribution Model.
What is the Binomial Distribution Model?
The Binomial Distribution Model is a mathematical model of probability that allows one to decipher the probability of success of a group of possibilities within a range of specifically repeated processes.
What is the calculation for the above?
Given that non-losing tickets (n) is: 5
Tickets gotten with non-losing probability p = 2/5 = 0.4
Note that probability here is given as:
Pr [X ≥ 3] = [tex]\sum_{x=3}^{5}.[/tex][tex]\binom{n}{x}[/tex] pˣ (1-p)ⁿ⁻ˣ
→ [tex]\sum_{x=3}^{5}.[/tex][tex]\binom{n}{x}[/tex] (0.4)ˣ (0.6)⁵⁻ˣ
= 992/3125
= 0.31744
Learn more about binomial distribution at:
https://brainly.com/question/14565246
#SPJ1
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.