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Sagot :
The vapour pressure in the water flask is 23.686 torr.
The pressure of [tex]H_2[/tex] in the flask was 713.514 torr.
Pressure is the [tex]H_2[/tex] exerting in the flask is 688.314 torr
What is vapour pressure?
Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature.
a.The vapour pressure of water is given by:
[tex]Log_{10} P =A- \frac{B}{C+T}[/tex], where T is in degree Celcius, P is in torr.
For 0-100 degree celcius, A=8.07131, B=1730.63, C=233.426
[tex]Log_{10} P = 8.07131 - \frac{1730.63}{233.426+25} =1.3745[/tex]
As T =25 degree celcius
[tex]P = 10^{1.3745} torr[/tex] =23.686 torr
b.We know that [tex]P_{total} =P_{H_2} + P_{H_2O}[/tex]
[tex]P_{total}[/tex] = Atmospheric pressure
[tex]737.2 torr = P_{H_2} +23.686 torr[/tex]
[tex]P_{H_2} = 713.514 torr[/tex]
c.After there is a leak in the gas collection tube, the amount at pressure due to water vapour remains unchanged as it is a quantity dependent on temperature.
[tex]P_{total} =P_{H_2} + P_{H_2O} + P_{leaking \;air}[/tex]
[tex]737.2 torr = P_{H_2} + 23.686 torr + 25.2 torr[/tex]
[tex]P_{H_2} =688.314 torr[/tex]
For calculating molar mass of any gas:
M= Density X (RT ÷ P)
M= 0.714 g X ([tex]8.314 J mol^{-1}K^{-1}[/tex]273 K ÷ 101325 Pa)
M= 15.994 g/mol = 16 g/mol.
Learn more about vapour pressure here:
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