roseandjack3
Answered

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Two piecewise functions are shown below. What is the value of
6f (-2) + 3g (1)?
f(x) =
0-7
O-25
1/3
O 18
{
-3x
*+2'
if x < -2
³, if x ≥-2
(2|x-1| +3,
-5√x+3-1,
g(x) =
={
if x ≤ 1
if x > 2

Two Piecewise Functions Are Shown Below What Is The Value Of 6f 2 3g 1 Fx 07 O25 13 O 18 3x 2 If X Lt 2 If X 2 2x1 3 5x31 Gx If X 1 If X Gt 2 class=

Sagot :

reinhard10158

Step-by-step explanation:

I am not sure what your problem here is.

you understand the inequality signs ?

anyway, to get

6×f(-2) + 3×g(1)

we can calculate every part of the expression separately, and then combine all the results into one final result.

f(-2)

we look at the definition.

into what category is -2 falling ? the one with x<-2, or the one with x>=-2 ?

is -2 < -2 ? no.

is -2 >= -2 ? yes, because -2 = -2. therefore, it is also >= -2.

so, we have to use

1/3 x³

for x = -2 that is

1/3 × (-2)³ = 1/3 × -8 = -8/3

g(1)

again, we look at the definition.

into what category is 1 falling ? the one with x > 2 ? or the one with x <= 1 ?

is 1 > 2 ? no.

is 1 <= 1 ? yes, because 1=1. therefore it is also <= 1.

so we have to use

2×|x - 1| + 3

for x = 1 we get

2×0 + 3 = 3

6×f(-2) = 6 × -8/3 = 2× -8 = -16

3×g(1) = 3× 3 = 9

and so in total we get

6×f(-2) + 3×g(1) = -16 + 9 = -7

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