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Given: a || b, transversal k
Prove <3 = <6

Given A B Transversal K Prove Lt3 Lt6 class=

Sagot :

By the property of corresponding angles  ∠3 ≅ ∠5.

What is transversal line?

In geometry, a transversal is any line that intersects two straight lines at distinct points.

If two parallel lines are cut by a transversal, then each pair of corresponding angles are equals.

That is, ∠3 = ∠5 and ∠4 = ∠6.

Therefore the given angles ∠3 and ∠5 are equal.

Hence  ∠3 ≅ ∠5 .

Know more about transversal line here :

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