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Use the formula to solve the equation x^2 + 9x + 8 = 0.

Sagot :

Hamster01100

Answer:

[tex]x=-8, -1[/tex]

Step-by-step explanation:

Given the equation [tex]x^{2} +9x+8=0\\[/tex],

By the quadratic formula,

[tex]x=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex],

[tex]x=\frac{-(9)+-\sqrt{(9)^{2}-4(1)(8) } }{2(1)}=\frac{-9+-\sqrt{49 } }{2}=\frac{-9+-7 }{2}[/tex]

We have two different solutions for x where [tex]x=\frac{-9-7 }{2}[/tex] and [tex]x=\frac{-9+7 }{2}[/tex]

So, x = [tex]-16/2=-8[/tex] and [tex]x=-2/2=-1[/tex]

Therefore, the solutions to this quadratic equation is x = -8, -1, by the quadratic formula.

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