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A sample of substance x that has a mass of 326.0 g releases 4325.8 cal when it freezes at its freezing point. if substance x has a molar mass of 58.45 g/mol, what is the molar heat of fusion for substance x? use q equals n delta h.. 13.31 cal/mol 74.00 cal/mol 775.6 cal/mol 19054.7 cal/mol

Sagot :

Eduard22sly

The molar heat of fusion for substance X , given the data is 775.6 cal/mol

How to determine the mole of the substance X

  • Mass = 326 g
  • Molar mass = 58.45 g/mol
  • Mole = ?

Mole = mass / molar mass

Mole = (326 / 58.45) moles

How to determine the heat of fussion

  • Mole (n) = (326 / 58.45) moles
  • Heat (Q) = 4325.8 cal
  • Heat of fusion (ΔHf) = ?

Q = n × ΔHf

4325.8 = (326 / 58.45) × ΔHf

4325.8 = (326 × ΔHf ) / 58.45

Cross multiply

326 × ΔHf = 4325.8 × 58.45

Divide both sides by 326

ΔHf = (4325.8 × 58.45) / 326

ΔHf = 775.6 cal/mol

Learn more about heat transfer:

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