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Sagot :
Thus, for drawing the graph for y = 3/4x + 7.
For drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.
How to know if a point lies in the graph of a function?
All the points (and only those points) which lie on the graph of the function satisfy its equation.
Thus, if a point lies on the graph of a function, then it must also satisfy the function.
For this case, the equation given to us is:
y=3/4x+7
Any equation of the form y=mx+c where m and c are constants and x and y are variables is the equation of a straight line.
For a straight line to be characterized, only two points are sufficient.
For x = 0, the y-coordinate would be such that it would satisfy the equation
y=3/4x+7
Putting x = 0, we get:
y=3/4(0)+7
y=7
Thus, the y-coordinate of the point on this line whose x-coordinate is 0 is 7. Thus, (0,7) is one of the point coordinates on the considered line.
Putting x = 3, we get:
y=3/4(3)+7
y=9.25
Thus, the y-coordinate of the point on this line whose x-coordinate is 0 is 9.25. Thus, (0,9.25) is another of the point's coordinates on the considered line.
Thus, for drawing the graph for y = 3/4x + 7, a person can draw a point at x of 0 and y of __7_, a second point by going over 3 and up __8.25__, and then draw a line through the points.
Learn more about points lying on the graph of a function here:
brainly.com/question/1979522
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