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A rectangular room is 1.2times as long as it is wide, and its perimeter is
30 meters. Find the dimension of the room.
The length is :
meters and the width is
___meters.


Sagot :

The length is 6.8 meters and the width is 8.2 meters.

How to determine the dimension of the room?

Represent the length and the width with x and y

So, we have:

y = 1.2x

P = 2(x + y)

The perimeter is 30.

So, we have:

2(x + y) = 30

Divide by 2

x + y = 15

Substitute y = 1.2x

x + 1.2x = 15

This gives

2.2x = 15

Divide by 2.2

x = 6.8

Substitute x = 6.8 in y = 1.2x

y = 1.2 * 6.8

Evaluate

y = 8.2

Hence, the length is 6.8 meters and the width is 8.2 meters.

Read more about perimeter at:

https://brainly.com/question/24571594

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