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Sagot :
The length is 6.8 meters and the width is 8.2 meters.
How to determine the dimension of the room?
Represent the length and the width with x and y
So, we have:
y = 1.2x
P = 2(x + y)
The perimeter is 30.
So, we have:
2(x + y) = 30
Divide by 2
x + y = 15
Substitute y = 1.2x
x + 1.2x = 15
This gives
2.2x = 15
Divide by 2.2
x = 6.8
Substitute x = 6.8 in y = 1.2x
y = 1.2 * 6.8
Evaluate
y = 8.2
Hence, the length is 6.8 meters and the width is 8.2 meters.
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