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How many moles of CF4 can be produced when 8.95 mol C reacts with 7.88 mol F2?
How many moles of each reactant are left over? (Note that at least one of the reactants must disappear.)
C remaining
mol
F2 remaining
mol

Sagot :

onyebuchinnaji

The remaining moles of C is 5.01 moles while the remaining moles of F₂ is 0.

Reaction between Carbon and Fluorine

The reaction between carbon and Fluorine is given as;

C + 2F₂  -------> CF₄

1  :    2                1

from the reaction above,

2 moles of F₂ requires 1 mole of C

7.88 mole of  F₂ will require:    7.88/2 = 3.94 moles of C and 3.94 moles of CF₄.

The remaining moles of C = 8.95 - 3.94 = 5.01 moles while the remaining moles of F₂ is 0.

Learn more about moles here: https://brainly.com/question/15356425

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