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Sagot :

snehashish65

The third charge is in equilibrium, 2a/3

What is electric field?

An electric property associated with each point in space when charge is present in any form.

The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.

According to the question,

force on it due to +4e= force due to +e

[tex]\frac{ k(4e)q}{x^{2} } = \frac{ k(e)q}{(a-x)^2}[/tex]

4(a-x)² = x²

2(a-x)=x

2a-2x =x

x= [tex]\frac{2a}{3}[/tex]

Therefore,

The position along the line XY is [tex]\frac{2a}{3}[/tex]

Learn more about Electric field here:

https://brainly.com/question/15800304

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