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a A load of 1000 N can be lifted by applying
the force) effort of 250 N.If the load
arm is 25 cm, calculate the effort arm.



Sagot :

Answer:

Explanation:

[tex]\text{Since the fulcrum lies in between the load and effort, it is class I lever.}[/tex]

[tex]\text{Mechanical advantage (M.A.) of levers is given by,}[/tex]

[tex]\text{M.A.=effort armload arm=50cm,10cm}[/tex]

[tex]\text{Thus, mechanical advantage , M.A. = 5.}[/tex]

[tex]\text{Given, effort (E)=10N, Load(L)=?}[/tex]

∴ [tex]L=E \times M.A.[/tex]

[tex]=10\times5=50N[/tex]

Answer:

[tex]\fbox {100 cm}[/tex]

Explanation:

Finding Mechanical Advantage :

MA = Load / Effort

MA = 1000/250

MA = 4

Finding length of effort arm :

Load arm = Effort arm / 4

Effort arm = 25 cm x 4

Effort arm = 100 cm

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