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PLEASE HELP FAST! How many grams of NO are formed if 8.3 g of ammonia react with 11.8 g of oxygen? The reaction is 4NH3 + 5O2 --> 4NO + 6H2O.

Options:
A. 8.85 g NO
B. 12.6 g NO
C. 14.6 g NO
D. 9.3 g NO


Sagot :

The mass of NO produced is 9.3 g; option D.

What mass of NO is produced from the reaction?

The mass of nitrogen (ii) oxide, NO, produced from the reaction is determined from the mole ratio of the reaction.

The mole ratio of ammonia to oxygen from the equation of the reaction is 4 : 5.

moles of oxygen = 11.8/32 = 0.368

moles of ammonia = 8.3/17 = 0.488

Oxygen is the limiting reactant.

Mass of NO produced = 0.369 * 4/5 * 30 = 9.4 g NO

In conclusion, approximately 9.3 g of NO is produced.

Learn more mole ratio at: https://brainly.com/question/19099163

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