Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

If you had 6 mol of oxygen and 12 mol of mercury, what would be the limiting reactant? show your work

Sagot :

Eduard22sly

The limiting reactant between the reaction of 6 moles of oxygen and 12 moles of mercury is mercury (Hg)

Balanced equation

4Hg + O₂ —> 2Hg₂O

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

How to determine the limiting reactant

From the balanced equation above,

4 moles of Hg reacted with 1 mole of O₂

Therefore,

12 moles of Hg will react with = 12 / 4 = 3 moles of O₂

From the above calculation, we can see that only 3 moles of O₂ out of 6 moles given is required to react completely with 12 moles of Hg.

Thus, Hg is the limiting reactant and O₂ is the excess reactant .

Learn more about stoichiometry:

https://brainly.com/question/14735801

#SPJ1

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.