The heat of vaporization of water is 540 cal/g. How much heat is needed to change 4.28g of water to steam?

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02-07-2022
Chemistry

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The heat of vaporization of water is 540 cal/g. How much heat is needed to change 4.28g of water to steam?

Sagot :

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jsimpson11000 jsimpson11000 · Answer 1 · 2022-07-04T17:34:12-04:00

jsimpson11000 jsimpson11000

04-07-2022

Answer:

2311.2 cal

Explanation:

540 cal / g * 4.28 g = 2311.2 cal

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kumaripoojavt kumaripoojavt · Answer 2 · 2022-07-22T00:15:48-04:00

2311.2 cal heat is needed to change 4.28g of water to steam.

What is heat?

Heat is the transfer of kinetic energy from one medium or object to another, or from an energy source to a medium or object.

The heat of vaporization is defined as the amount of heat needed to turn 1g of a liquid into a vapour, without a rise in the temperature of the liquid.

The heat of vaporization is equal to the thermal energy required for vaporization divided by the mass of the substance that is vaporizing. Its formula is Hv = q/m.

Putting the values in the formula:

540 cal / g x 4.28 g = 2311.2 cal

Hence, 2311.2 cal heat is needed to change 4.28g of water to steam.

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What is heat?

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