Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The heat of fusion of water is 79.9cal/g, the heat of vaporization of water is 540cal/g, and the specific heat of water is 1.00cal/deg/g. How much ice at 0 celsius could be converted to steam at 100 celsius by 9522cal of heat?

Sagot :

The amount of ice converted into steam is 13.23 gram.

What is Heat of Vaporisation ?

Heat of Vaporisation is the amount of heat required to convert 1 gm to liquid at its boiling point to vapour.

Let x gram of ice is there

At first x gm of ice will melt

The heat required is x * Heat of fusion = x * 79.9 = 79.9x

Then the heat required to rise the temperature of x gm of water from 0 degree to 100 degree Celsius .

= mc ΔT

= x * 1 * 100 = 100x

The heat required to convert x gm of liquid into x gm of steam

= x * 540 = 540x

The total heat supplied is 9522 cal

79.9x + 100x + 540x = 9522

719.9 x = 9522

x = 13.23 gm

The amount of ice converted into steam is 13.23 gram.

To know more about Heat of Vaporisation.

https://brainly.com/question/9967928

#SPJ1