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Sagot :
Let's take this problem step-by-step:
Let's convert the equation back into the standard form:
⇒ standard form: (x-h)² +(y-k)² = r²
- (h, k): center's coordinate
- r: radius
[tex]x^2+y^2-8x+10y + 37 = 0\\\rm \hookrightarrow x^2 - 8x + y^2+10y = -37\\\rm \hookrightarrow (x^2 - 8x) + (y^2 + 10y) = -37\\\rm \hookrightarrow (x^2-8x+16) + (y^2+10y+25) = -37 + 16 +25\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 4\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 2^2[/tex]
Based on the equation found
⇒ center: (4, -5)
⇒ radius: 2
Answer:
- center: (4, -5)
- radius: 2
Hope that helps!
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