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What volume of a 3.95 M
potassium chloride solution would
be needed to make 325 mL of a
2.76 M solution by dilution?
[?] mL of 3.95 M KCl

What Volume Of A 395 M Potassium Chloride Solution Would Be Needed To Make 325 ML Of A 276 M Solution By Dilution ML Of 395 M KCl class=

Sagot :

0.227L is the volume of a 3.95 M potassium chloride solution that would be needed to make 325 mL of a 2.76 M solution by dilution.

What are moles?

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Moles of KCl in new solution

0.325dm³ x (2.76mol/dm³)

= 0.897mol.

Hence volume needed

0.897mol ÷(3.95mol/dm³)

= 0.227dm³ or 0.227L.

Learn more about moles here:

https://brainly.com/question/8455949

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