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Sagot :
0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
What is a photon?
A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic (or light) energy.
We need to find the number of photons emitted per second.
So we have E = hc ÷ λ
= (6.6 x [tex]10^-(^3^4^)[/tex]x 3 x [tex]10^8[/tex] m/s) ÷ 6.78 x [tex]10^(^-^7^)[/tex]nm
= 2.92 x [tex]10^(^-^1^9^)[/tex]Joules
Now number of photons per second = I / E (I = intensity)
= 1 x [tex]10^(^-^3^)[/tex] joule / sec ÷ 2.92 x [tex]10^(^-^1^9^)[/tex]joule
= 0.342 x[tex]10^(^1^6^)[/tex]
Hence, 0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
Learn more about the photon here:
https://brainly.com/question/14838916
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