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Factorise completely

qn: 12axy + 8bxy + 4xy

Sagot :

Answer:

Step-by-step explanation:

View image mbaratiz

Answer:

4xy(3a+2b+1)

Step-by-step explanation:

1)  Find the Greatest Common Factor (GCF).

1 - What is the largest number that divides evenly into 12axy, 8bxy and 4xy?

It is 4.

2 -  What is the highest degree of [tex]a[/tex]  that divides evenly into 12axy, 8bxy and 4xy?

It is 1, since a is not in every term.

3 -  What is the highest degree of [tex]x[/tex] that divides evenly into 12axy, 8bxy and 4xy?

It is x.

4 - What is the highest degree of [tex]y[/tex]  that divides evenly into  12axy, 8bxy and 4xy?

It is y.

5 -  What is the highest degree of [tex]b[/tex] that divides evenly into 12axy, 8bxy and 4xy?

It is 1, since [tex]b[/tex] is not in every term.

6 - Multiplying the results above,

GCF = 4xy

2)  Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

[tex]4xy(\frac{12axy}{4xy} +\frac{8bxy}{4xy} +\frac{4xy}{4xy} )[/tex]

3) Simplify each term in parentheses.

[tex]4xy(3a+2b+1)[/tex]