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OX and OY are two straight lines which intersect at an acute angle of 60°. OX = 4.5cm and OY = 5cm . The point M is on OX such that OM = 2MX Find a point P within the acute angle formed by OX and OY which is always the same distance from OX and OY and 3 cm from M.​

Sagot :

Therefore the point P is at 3.46 cm from O and it lies on the angle bisector of ∠XOY

What is an Angle Bisector ?

The ray that bisects the angle into half is called Angle Bisector.

It is given that ∠XOY = 60 degree

the length of OX = 4.5 cm

OY =5 cm

The point M is on OX such that

OM = 2 MX

so The M is at 3 cm from O

The point P lies in the acute angle such that the distance between point P and OX and OY is always same and at 3 cm from M

According to the angle bisector theorem converse states that if a point is in the interior of an angle and is at equal distance from the sides  then it lies on the bisector of that angle.

As it can be seen from the image that a point equidistant from the rays , at 3 cm from M will be at

By Pythagoras Theorem

3² +3² = OP²

OP = 2[tex]\sqrt{3}[/tex] = 3.46 cm from O

To know more about Angle Bisector

https://brainly.com/question/12896755

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