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In AABC, a = 13, b = 14, and c = 18. Find m/A.
B
A
39.5
с
b
a

Sagot :

Medunno13

Answer:

Step-by-step explanation:

Using the Law of Cosines,

[tex]a^{2}=b^2 + c^2 - 2bc \cos A\\\\13^{2}=14^{2}+18^{2}-2(14)(18) \cos A\\\\-351=-504 \cos A\\\\\cos A=\frac{351}{504}\\\\A=\boxed{\cos^{-1} \left(\frac{351}{504} \right)}[/tex]

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