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1 gal of KCL solution by mixing 565 g of KCL in an appropriate vehicle. How many milliequivalents of K are in 15 ml of this solution

Sagot :

Snor1ax

Answer: 30 meq

Explanation:

We know that 1 gallon = 3.785 Litres

1 litre = 1000 milliliters

1 gallon = 3785 ml

Concentration = weight/volume

= 565/3785

= 0.149 g/ml

= 149 mg/ml

Multiplying with 15 ml we get

= 149*15 = 2235 mg

The atomic weights of:

Potassium (K) = 39

Chlorine (Cl) = 35.5

Finding the equivalent weight of Kcl = 39 + 35.5 = 74.5

So, 1 equivalent of KCl is 74.5 g

= 2235 mg * 1 meq/74.5 mg = 30 meq K+

Therefore, there are 30 milliequivalents of K in 15 ml of this solution

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