08761
Answered

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x = √3 + √2/ √3 - √2
y = √3 - √2/ √3 + √2
Find x² + y²

Sagot :

fieryanswererft

Answer: 98

Given following:

[tex]\Longrightarrow \sf x = \dfrac{\sqrt{3} +\sqrt{2} }{\sqrt{3} - \sqrt{2} }[/tex]

[tex]\Longrightarrow \sf y = \dfrac{\sqrt{3} -\sqrt{2} }{\sqrt{3} + \sqrt{2} }[/tex]

Solve for x² + y²:

[tex]\rightarrow \sf \left(\:\dfrac{\sqrt{3}\:+\sqrt{2}\:\:}{\sqrt{3}\:-\:\sqrt{2}\:}\right)^2\:+\:\left(\dfrac{\sqrt{3}\:\:-\sqrt{2}\:\:}{\sqrt{3}\:+\:\sqrt{2}\:\:}\:\right)^2[/tex]

simplify following

[tex]\rightarrow \sf 49+20\sqrt{6}+49-20\sqrt{6}[/tex]

add/subtract similar terms

[tex]\rightarrow \sf 98[/tex]

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