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Solve the problem.
The length of a rectangular room is 9 feet longer than twice the width. If the room's perimeter is
198 feet, what are the room's dimensions?

Sagot :

e348779760

Answer:

width is 30, and the length 69.

Step-by-step explanation:

In order to do this, we need to do ALGOOBRAA

lets say x is equal to the width of the room

then, that means the length is (9+2x) Sooooo,

198=2x+2(9+2x)

Using the distributive property, we know that

2(9+2x)=18+4x

If you dont know what that is, then go search it up :/

so,

198=2x+18+4x

198=6x+18

180=6x

30=x

BAM

Now, we know that the width is 30, bro.

That means the length is 60+9, Which is 69.

Therefore, the width is 30, and the length 69.

Sry if im wrong btw.

ashishdwivedilVT

The width of rectangle is 30, and the length is 69.

What is Rectangle?

A rectangle is a quadrilateral. The opposite sides of a rectangle are equal and parallel to each other. The interior angle of a rectangle at each vertex is 90°. The sum of all interior angles is 360°. The diagonals bisect each other.

Here, lets say x is equal to the width of the room

then, that means the length is (9+2x) So,

              198 = 2x+2(9+2x)

Using the distributive property, we know that

                 2(9+2x)=18+4x

If you don't know what that is, then go search it up :/

so,

               198 = 2x+18+4x

                198=6x+18

                 180=6x

                  30=x

Now, we know that the width is 30,

That means the length is 60+9, Which is 69.

Thus, the width of rectangle is 30, and the length is 69.

Learn more about Rectangle from:

https://brainly.com/question/15019502

#SPJ1

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