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A syringe containing 35.0 mL of Xe gas at 298 K has a pressure of 0.980 atm. How many grams of Xe are in the syringe? Report your answer to the nearest 0.001 g

Sagot :

Eduard22sly

The mass of Xe present in the syringe given the data is 0.183 g

How to determine the mole of Xe

  • Volume (V) = 35 mL = 35 / 1000 = 0.035 L
  • Pressure (P) = 0.980 atm
  • Temperature (T) = 298 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

Using the ideal gas equation, we can obtain the mole of Xe as follow:

n = PV / RT

n = (0.98 × 0.035) / (0.0821 × 298)

n = 0.0014 mole

How to determine the mass of Xe

  • Mole = 0.0014 mole
  • Molar mass of Xe = 131 g/mole
  • Mass of Xe = ?

Mass = mole × molar mass

Mass of Xe = 0.0014 × 131

Mass of Xe = 0.183 g

Learn more about ideal gas equation:

https://brainly.com/question/4147359

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