At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
NO is the limiting reagent and 4.34 g is the amount of the excess reagent that remains after the reaction is complete
What is a limiting reagent?
The reactant that is entirely used up in a reaction is called as limiting reagent.
The reaction:
[tex]2NO(g) +2H_2(g)[/tex] → [tex]N_2 +2H_2O[/tex]
Moles of nitrogen monoxide
Molecular weight: [tex]M_(_N_O_)[/tex]=30g/mol
[tex]n_(_N_O_) =\frac{mass}{molar \;mass}[/tex]
[tex]n_(_N_O_) =\frac{22.0}{30g/mol}[/tex]
[tex]n_(_N_O_) = 0.73 mol[/tex]
Moles of hydrogen
Molecular weight: [tex]M_(_H_2_)[/tex]=30g/mol
[tex]n_(_H_2_) =\frac{mass}{molar \;mass}[/tex]
[tex]n_(_H_2_) =\frac{5.80g}{2g/mol}[/tex]
[tex]n_(_H_2_) = 2.9 mol[/tex]
Hydrogen gas is in excess.
NO is the limiting reagent.
The amount of the excess reagent remains after the reaction is complete.
[tex]n_(_N_2_) =[/tex] (2.9 mol- 0.73 mol NO x [tex]\frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}[/tex]) x [tex]\frac{2g \;of \;H_2}{mole \;of \;H_2}[/tex]
[tex]n_(_N_2_) =[/tex]4.34 g
Learn more about limiting reagents here:
https://brainly.com/question/26905271
#SPJ1
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
