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How many grams of glucose (C6H12O6) are contained in 555 mL of a 1.77 M glucose solution?

Sagot :

176.980176 g of glucose ([tex]C_6H_{12}O_6[/tex]) are contained in 555 mL of a 1.77 M glucose solution.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]1.77 M = \frac{Moles \;solute}{0.555 L}[/tex]

mole solute = 0.98235 g/mol

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]0.98235 g/mol = \frac{mass}{180.16 g/mol}[/tex]

mass = 176.980176 g

Hence, 176.980176 g of glucose ([tex]C_6H_{12}O_6[/tex]) are contained in 555 mL of a 1.77 M glucose solution.

Learn more about moles here:

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