Answered

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Calculate the pH of a solution that is 0.113 M HCI.

Sagot :

Simplified concentration

[tex]\\ \rm\Rrightarrow 1.13\times 10^{-2}M[/tex]

Now

[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]

[tex]\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})[/tex]

[tex]\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}[/tex]

[tex]\\ \rm\Rrightarrow pH=-0.05+2[/tex]

[tex]\\ \rm\Rrightarrow pH=1.95[/tex]

Highly acidic

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