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Sagot :
Answer: Choice C [tex]f(x) = 5(x+4)^2 - 80[/tex]
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Reason:
The expression [tex]x^2+8x+16[/tex] factors to [tex](x+4)^2[/tex] using the perfect square trinomial formula [tex](a+b)^2 = a^2 + 2ab + b^2[/tex]. In this case, a = x and b = 4.
The -5(16) simplifies to -80
Therefore, [tex]5(x^2+8x+16) - 5(16)[/tex] turns into [tex]5(x+4)^2 - 80[/tex]
Compare this to [tex]a(x-h)^2 + k[/tex] to see that h = -4 and k = -80. The vertex is located at (h,k) = (-4, -80)
Answer:
c) 5(x+4)² - 80
Step-by-step explanation:
You have already gotten the third (second-last) step for finding the vertex as follows:
f(x) = 5(x² + 8x + 16) -5(16)
= 5(x+4)² - 80
Additional remarks: to find the vertex, you can just use find the value of x when x+4 = 0, meaning x = -4 and y = -80. Hence, the vertex is (-4, -80).
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