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A car of mass 750 kg accelerates away from traffic lights. At the end of the first 100 m it has reached a speed
of 12 m/s. During this time, its engine provides an average forward force of 780 N, and the average force of
friction on the car is 240 N.
a Calculate the work done on the car by the force of its engine.
b Calculate the work done on the car by the force of friction.
c Using ke. = mv2, calculate the increase in the car's kinetic energy at the end of the first 100 m.
d Explain whether your answers are consistent with the principle of conservation of energy.​

Sagot :

abbusaicharan02

the work done on the car by the force of its engine is 78,000 J.

" The work done on the car by the force of friction is 24,000 J.

Increasing the car's kinetic energy at the end of the first 100 m is 54,000J

a. Completed work = force x distance. Engine output = 780 N, that is,

780 N x 100 m = 78,000 J.

b. Completed work = force x distance. Friction force = 240 N, that is,

240 N x 100 m = 24,000 J.

c. Kinetic energy = 1 \ 2 x m x v2

= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.

How powerful is the engine of a car?

Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.

Learn more about work done here:  https://brainly.com/question/25573309

#SPJ10

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