greatkalyan5
Answered

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A bus start from rest. If the acceleration of bus is 0.5 m/s square. what will be its velocity at the end of 2 minutes?what will be the distance cover?​

Sagot :

Answer:

3586

Explanation:

by using formula s=it+0.5at^2

Answer:

[tex]\fbox {Velocity = 60 m/s, Distance = 3600 m}[/tex]

Explanation:

Part (i) : Velocity at end of 2 minutes

Equation used ⇒ [tex]\boxed {v = u + at}[/tex]

⇒ t = 2 minutes = 2 x 60 = 120 seconds

⇒ v = 0 + (0.5)(120)

⇒ v = 60 m/s

Part (ii) : Distance covered

Equation used ⇒ [tex]\boxed {S = \frac{v^{2}-u^{2}}{2a}}[/tex]

⇒ S = (60)² - (0)² / 2(0.5)

⇒ S = 3600 m

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