Answered

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he given line passes through the points and (4, 1).

On a coordinate plane, a line goes through (negative 4, negative 3) and (4, 1).

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (, 3)?

Sagot :

varshamittal029

The equation of the line that passes through the point (-4 , 3) with slope ₋2 is:

y = ₋2x ₋ 5

Given the points are (₋4 , ₋3) and (4 , 1)

The gradient of the line through the points' locations (x₁ , y₁) and (x₂ , y₂) is:  y₂ ₋ y₁/x₂ ₋ x₁

Substitute the given points in the above formula:

=1 ₋(₋3)/4 ₋ (₋4)

=4/8

=1/2

If the product of the slopes of two perpendicular lines is -1, then the slope of the perpendicular line is ₋1/1/2 = ₋2

Therefore the line that passes through the point (-4 , 3) with slope ₋2 has equation:

y ₋ 3 = ₋2(x ₊ 4)

y = ₋2x ₋ 8 ₊ 3

y = ₋2x ₋ 5

Hence we get the expression as y = ₋2x ₋ 5

Learn more about "intercept forms" here-

brainly.com/question/6202710

#SPJ10

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