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Sunil draws a regular hexagon and a convex quadrilateral on a sheet of paper, so that no side of the quadrilateral lies on the same line as a side of the hexagon. what is the maximum total number of points in which the sides of the quadrilateral can intersect the sides of the hexagon?

Sagot :

tushargupta0691

Maximum total 8 points in which the sides of the quadrilateral can intersect the sides of the hexagon.

A regular hexagon is a closed shape polygon which has six equal sides and six equal angles. In case of any regular polygon, all its sides and angles are equal.

A convex quadrilateral is a four-sided polygon that has interior angles that measure less than 180 degrees each. The diagonals are contained entirely inside of these quadrilaterals

Take a look at just one side of the quadrilateral—a straight line. Since we are told that no side of the quadrilateral lies on the same line as a side of the hexagon, the maximum number of times a side of the quadrilateral could intersect the hexagon is 2. We can use a ruler to test this on the image of the hexagon. There is no way to pass a straight line through the hexagon and have it intersect the shape more than 2 times. Therefore, the maximum number of points at which the quadrilateral could intersect the hexagon would be

at 2 points per side, at 2 × 4 = 8 points.

Hence, Maximum total 8 points in which the sides of the quadrilateral can intersect the sides of the hexagon.

Learn more about convex quadrilaterals here :

https://brainly.com/question/15115269

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